引用定位

时间：2011-05-16 15:55:57 来源：站内作者：潘春会

($v)
{
$v->d = 1225;
}

$A = new yy(3);
var_dump($A);
modify($A);
var_dump($A);
?>

Although, in general, a formal argument declared
as $v in the function 'modify' shown above, implies
that the actual argument $A, passed when calling
the function, is not modified, this is not the
case when $A is an object instance. See what the
example code outputs when executed:

object(yy)#3 (1) {
["d"]=>
int(3)
}
object(yy)#3 (1) {
["d"]=>
int(1225)
}

Sergio Santana: ssantana at tlaloc dot imta dot mx (11-Aug-2005 12:30)

Sometimes an object's method returning a reference to itself is required. Here is a way to code it:



<?php

class MyClass {

  public $datum;

  public $other;

  

  function &MyRef($d) { // the method

    $this->datum = $d;

    return $this; // returns the reference

  }

}



$a = new MyClass;

$b = $a->MyRef(25); // creates the reference



echo "This is object $a: n";

print_r($a);

echo "This is object $b: n";

print_r($b);



$b->other = 50;



echo "This is object $a, modified" .

     " indirectly by modifying ref $b: n";

print_r($a);

?>



This code outputs:

This is object $a:

MyClass Object

(

    [datum] => 25

    [other] =>

)

This is object $b:

MyClass Object

(

    [datum] => 25
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